Ahmed S.
asked • 01/14/24Geometric series problem
State the values of term 1 and the common ratio. Then, determine the partial sum. (I am stuck trying to find the partial sum. Please help)
0.43 + 0.0043 + 0.000043 + . . ., + (S6)
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1 Expert Answer
Raymond B. answered • 01/14/24
Tutor
5
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Math, microeconomics or criminal justice
r= .01 = 1/100
Sn= a1(1-r^n)/(1-r) = partial sum of a geometric series where a1= 1st term= .43 = 43/100, n= number of terms=6, r= common ratio= .01=1/100
S6 = .43(1-(.01)^6/(1-.01)= sum of 1st 6 terms (a calculator is handy at this point)
= .434343...
= 43/99
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Doug C.
01/14/24