Rachel M.

asked • 01/09/24

Clarification on equation of the sphere

Find the equation of the sphere of radius 6 that lies above the xy-plane that just touches the xy-plane at the point (3, −7, 0).


answer: (x-3)^2 + (y+7)^2 + (z-6)^2 = 6^2

It is on the xy-plane why do we add in the z part with the radius? Is it because z will eventually cancel out and become zero.

Doug C.

Ask yourself where is the center of the sphere? If it is tangent to the xy-plane at (3,-7,0), then a line through that point parallel to the z-axis will contain a diameter of the sphere. Since the radius is 6, up 6 along that line takes you to the point (3, -7,6)--the center of the sphere. Take a look here: desmos.com/3d/a8ba557f46
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01/09/24

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