factor the trinomial "6x^2+17x-14"

Answer 1

x₁=(-17/12)+(√17²+4*6*14/)/12=(-17)/12+25/12=4/6

x₂=(-17/12)-(√17²+4*6*14)/12=(-17)/12-25/12=-21/6

from quadradic formula

x₁ and x₂ are when f(x)=0, f(x)=a(x-x₁)(x-x₂)

where a is known as 6

now have f(x)=6(x-4/6)(x+21/6)=[3*(x-4/6)][2*(x+21/6)

f(x)=(3x-2)(2x+7)