Ariel B. answered 12/24/23
Honors MS in Theor. Physics, solid Math. background and 10+tutoring
Hi Sam,
Graphs of the two lines forming R intersect at x=9
Therefore , the volume Vx of the body formed by the R rotating around x-axis (
Vx=∫[0,9] π{(√x)2-(x/3)2dx}=∫[0,9] π{[x-x2/9]dx}=
π{x2/2-x3/27}[0,9]
If R would be rotating around y-axis,
we can re-write the bordering lines as x=y2 and x=3y (meeting at y=3).the volume Vy of the body formed by the R rotating around y-axis would be
Vy=∫[0,3] π{[(3y)2-y4]dy}= π{(y3-y5/5)}[0,3]
The rest is to evaluate Vx at x=9 and Vy at y=3 b/c at lower ends [for x=0 Vx=0 and for y=0 Vy=0]
Hope it's helpful
Dr.Ariel B.
Reginald J.
I apologize as I solved only for rotation about the y-axis; I should’ve read closer for the rotation about x-axis also. Hopefully you can apply the same methodology.12/24/23