Distance = (Rate)(Time)
Let x = time jogging. Then 6 - x = time on scooter.
Distance to school = Distance from school
12(6 - x) = 6x
72 - 12x = 6x
18x = 72
x = 4 hours
Distance = (6 miles/hour)(4 hours) = 24 miles
Veronika W.
asked 12/19/23Jed rode his scooter to school at 12 miles per hour and then jogged back at 6 miles per hour. If the round trip took him 6 hours, how far was it to school?
Distance = (Rate)(Time)
Let x = time jogging. Then 6 - x = time on scooter.
Distance to school = Distance from school
12(6 - x) = 6x
72 - 12x = 6x
18x = 72
x = 4 hours
Distance = (6 miles/hour)(4 hours) = 24 miles
Let x represent his time riding the scooter.
Let y represent the time he jogged.
Note that y = 6 - x.
Therefore,
12x = distance from home to school
6y = 6(6-x) = distance from school to home
12x = 6(6-x) = 36 -6x
Add 6x to both sides of this equation:
18x = 36
Divide both sides by the coefficient of x, 18 in this case:
x = 2 hours.
12 miles per hour times 2 hours = 24 miles to school.
Check:
6*(6-2) = 6*4 = 24 miles home from school.
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