Raymond B. answered 12/17/23
Math, microeconomics or criminal justice
let y=x^2, then y^2 -3y + 2 = 0
factor
(y-1)(y-2) = 0
y = 1,2
x = plus or minus square root of y = 1,-1, sqr2, -sqr2
4 real solutions,
by Descartes' rule of signs there are 2 sign changes, so either 0 or 2 possible positive real solutions
and 0 or 2 negative real solutions
possible 0, 2 or 4 imaginary solutions
as it turns out there are 2,2 and 0 +,- and imaginary roots, solutions, zeros or x intercepts
try a graphing calculator, the graph crosses or touches the x axis 4 times