intermediate math

Question

The perimeter of a playing field for a certain sport is

314

ft. The field is a​ rectangle, and the length is

49

ft longer than the width. Find the dimensions.

Answer 1

Perimeter = 314=P

Length=49 feet more than width =49+w = L

P =2L+2w

314 = 2(49+w) +2w

divide by 2

107= 49+w +w

107 = 49 +2w

2w = 107-49

w = 58/2 = 29 feet wide

L= 49+29 = 78 feet Long

Perimeter = twice (Length+width)

314 = 2(78+29)=2(107)