p(x) = Ax2 + Bx + C = population, in millions, x years from the year 2000.
Since p(0) = 286, we get C = 286.
p(-10) = 100A - 10B + 286 = 252
p(10) = 100A + 10B + 286 = 312
100A - 10B = -34
100A +10B = 26
200A = -8
So, A = -1/25
100(-1/25) + 10B = 26
-4 + 10B = 26
10B = 30
B = 3
p(x) = (-1/25)x2 + 3x + 286
Anthony P.
I think you mis-read the question. There is no value given for x=20. Solving the 3x3 set of equations is probably what the math teacher wants. Interestingly, if the data are real-world (where measurements are never exact), doing a graph and fitting the data with both linear and quadratic equations suggests that a linear solution is probably (statistically and visually?) justifiable. . . . . . . ;-)12/13/23