(λ - 4)x + y = 0
So, y = -(λ - 4)x.
Therefore, x - (λ - 4)2x = 0
[1 - (λ - 4)2]x = 0
If x = 0, then, from the first equation y = 0 also. So, we get the trivial solution (0,0).
So, we can assume that x is nonzero.
Therefore, (λ - 4)2 = 1.
So, λ2 - 8λ - 17 = 0
λ = [8 ± √132] / 2 = 4 ± √33