Compute the derivative of the given function below

Question

y=₀∫^{e^x^2}dt/√t

dy/dx=?

Answer 1

Answer 2

y = ∫_{(from 0 to e^x}2₎ (1/√t)dt

dy/dx = [1 / √(e^{x^2})] d/dx(e^{x^2}) = 2xe^{x^2} [1 / √(e^{x^2})] = 2x√(e^{x^2})