A bacteria culture initially contains 3000 bacteria and doubles every half hour. Find the size of the baterial population after 80 minutes. Find the size of the baterial population after 9 hours.

Question

A bacteria culture initially contains 3000 bacteria and doubles every half hour.

Find the size of the baterial population after 80 minutes.   

Find the size of the baterial population after 9 hours.

Answer 1

0 3000

10 3000(2^.333...)

30 6000 = 3000(2^1)

60 12000= 3000(2^2)

90 24000 = 3000(2^3)

80 3000(2^2.666...)=about 19,048.81254 after 80 minutes

9 hrs= 540 minutes

540/30=18

540 3000(2^18)=786,432,000 after 9 hours