x intercepts of (x+6)²-7

Question

x intercepts of (x+6)²-7

Answer 1

y=(x+6)^2 -7=0

(x+6)^2= 7

x+6 = +/-sqr7

x = -6+sqr7, -6-sqr7 = the two x intercepts

= the points: (-6+sqr7, 0) and (-6-sqr7, 0)

= about -3.35,-8.65

axis of symmetry is x=-6

x intercepts are equidistant on either side of -6, -6+/-sqr7 = about -6+/-2.65