p(x) = -2x^2+280x-1000
The maximum (or minimum) of a quadratic function occurs at x= -b/2/a where (x) = ax2 + bx + c.
In this case, a = -2, b = 280, and c = -1000. Using the formula given, x = -280/2/(-2) = 70 items.
CIng K.
asked 12/02/23Suppose that the equation p(x) = -2x^2+280x-1000, where x represents the number of items sold, describes the profit function for a certain business. How many items should be sold to maximize the profit?
p(x) = -2x^2+280x-1000
The maximum (or minimum) of a quadratic function occurs at x= -b/2/a where (x) = ax2 + bx + c.
In this case, a = -2, b = 280, and c = -1000. Using the formula given, x = -280/2/(-2) = 70 items.
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