Mark M. answered 11/29/23
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
ey = x2/y
yey = x2
yey(dy/dx) + ey(dy/dx) = 2x
(dy/dx)(ey)(y + 1) = 2x
(dy/dx)(x2/y)(y + 1) = 2x
(dy/dx)(x2y + x2) = 2xy
dy/dx = 2xy / [x2(y + 1)] = 2y / [x(y+1)] = 2y / (xy + x)
Zara F.
Thank you so much!11/29/23