Hi Tra'von,
Given that this is a population, not a sample, formula is:
sd=sqrt[sum(xi-mu)2/n]
xi=Each individual x-value.
mu=mean
n=sample size
mu=(11+0+2+9+9+5)/6
mu=6
n=6
Now, we need sum(xi-mu)2 So:
(11-6)2 + (0-6)2 + (2-6)2 + (9-6)2 + (9-6)2 + (5-6)2 =96
But recall:
sd=sqrt[sum(xi-mu)2/n]
We now know sum(xi-mu)2 and n, so:
sd= sqrt(96/6)
sd=sqrt(16)
sd=4
Ultimately, you will likely use calculators or software to compute standard deviation, as the computation can get cumbersome when we have ten or more data points. I hope this helps.