Inactive Tutor answered 11/18/23
you have 10 paintings to be displayed 3 at a time.
the number of ways that they can be displayed is 10C3 = 10! / (3!)(7!)
that means (10 X 9 X 8) / (3 X 2) = 120.
so there are 120 ways to display the paintings.
Inactive Tutor answered 11/18/23
you have 10 paintings to be displayed 3 at a time.
the number of ways that they can be displayed is 10C3 = 10! / (3!)(7!)
that means (10 X 9 X 8) / (3 X 2) = 120.
so there are 120 ways to display the paintings.
Inactive Tutor answered 11/18/23
10P3 =10!/(10-3)! =10!/7!=720 ways
nPr=n!/(n-r)!, n=10, r=3
10!/7! = 10x9x8x7!/7!= 10x9x8 = 720
if order matters use the Permutation formula
for 10 objects taken 3 at a time
order matters means paintings displayed ABC, is a different way from BCA
if order doesn't matter, use the Combination formula
nCr = n!/(n-r)(r)! = 720/3x2 = 120 ways
combination means ABC is 1 way but BCA is not another way,both just 1 way
depending on how the problem is worded, its context
either might be right, 120 or 720
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.