Inactive Tutor answered 11/17/23
Answer:
10C3 = 10!/(10!-3!)*3!
= 10!/(7! x 3!)
= (10 x 9 x 8) / (3 x 2 x 1) -- 7! cancels out all the digits from 7 to 1 in 10!. 3! is left in the denominator
We end up with 720 / 6 = 120 combinations
Inactive Tutor answered 11/17/23
Answer:
10C3 = 10!/(10!-3!)*3!
= 10!/(7! x 3!)
= (10 x 9 x 8) / (3 x 2 x 1) -- 7! cancels out all the digits from 7 to 1 in 10!. 3! is left in the denominator
We end up with 720 / 6 = 120 combinations
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.