Raymond B. answered 11/16/23
Math, microeconomics or criminal justice
.1x +.13y = 507
x+y=4500
.1(4500-y)+.13y = 507
.03y = 57
y= 57/.03= $1900 at 13%
x=4500-1900= $2600 at 10%
.1(2600+.13(1900)=507
Paisley G.
asked 11/15/23Sara invested $4500 into two different accounts the first account paid 10% the second account paid 13% in interest at the end of the first year he earned $507 in interest how much was in each account
Raymond B. answered 11/16/23
Math, microeconomics or criminal justice
.1x +.13y = 507
x+y=4500
.1(4500-y)+.13y = 507
.03y = 57
y= 57/.03= $1900 at 13%
x=4500-1900= $2600 at 10%
.1(2600+.13(1900)=507
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