N = 500(0.08)0.7t represents the number of employees working t years after a company begins operations. (a) How many employees are there when the company opens (at t = 0)?

Answer 1

500 workers initially when the company opened, at time t=0

N(t)= 500(.08^.7t)

N(0) = 500(.08^.7(0)) =500(.08^0) = 500(1) = 500

any number raised to the zero power= 1

except 0^0 which =1 or is undefined depending on the context