3. Given that you have only 20 mL of a 0.300 M potassium hydroxide solution, what is the maximum volume of a 0.0750 M solution you can prepare using the entire stock solution?

Answer 1

To calculate the maximum volume of a 0.0750 M solution, you can prepare using the entire 20 mL of a 0.300 M potassium hydroxide solution, we can use the following formula:

M1​V1​=M2​V2​ where

1. M1​ is the molarity of the stock solution (0.300 M)
2. V1​ is the volume of the stock solution (20 mL)
3. M2​ is the molarity of the desired solution (0.0750 M)
4. V2​ is the volume of the desired solution

Plugging in the values,

we get: 0.300×20=0.0750×V2​V2​=0.07500.300×20​V2​=80



Therefore, the maximum volume of a 0.0750 M solution you can prepare using the entire 20 mL of a 0.300 M potassium hydroxide solution is 80 mL.