find the equation of a line perpendicular to 2x+2y=-2 that passes through the point (9,8)

Answer 1

To find the slope of the line, rewrite this equation in slope-intercept form (y=mx+b)

2x + 2y = -2

x + y = -1 [divide all terms by 2]

y = -x-1 [subtract x from both sides]

The slope of this line is -1 (the coefficient in front of the x term).

The slope of the line perpendicular to this line is the negative reciprocal of the slope of this line, which is -(1/-1) = 1.

We have the slope of the perpendicular line and a point that it passes through. Plug these values into the point slope form equation of a line: y-y₁=m(x-x₁), where (x1, y1) is a point the line passes through, and m is the slope.

y-8 = 1(x-9)

y = x-1

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Answer 2

2x + 2y = -2

So, y = -x - 1. The slope of this line is -1.

Slope of line perpendicular to the line with equation y = -x - 1 is -1 / (slope of given line) = 1

Equation of line with slope 1 and which contains the point (9,8): y - 8 = 1(x - 9). So, y = x - 1.