The Law of Sines

Question

Find the area of the triangle having the given measurements.

A=33 degrees, b=21 feet, c= 38 feet

Answer 1

area = (1/2)sin33(21)(38) = about 217.31 ft^2

area = (ab/2)sinC C=33, a=21, b=38 sin33=about .54464

area = one half the product of two sides of a triangle multiplied by sine of the angle between them

for another example, let C=90 degrees, sin C= 1, a=3, b=4, A = (1/2)(1)(3)4) = 6

a square 3 by 4 has A=12, the triangle has half the area of the square