
Yefim S. answered 11/10/23
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Volume v = x2y; x2 + 4xy = 2200; y = (2200 - x2)/4x; v = x[(2200 - x2)/4] = 550x - x3/4; v' = 550 - 3x2/4 = 0;
x = √2200//3 = 10√66/3; v'' = - 3x/2 < 0 at x = 10√66/3. So, we have maximum volume.
vmax = 10√66/3(550- 550/3) = 11000√66/9 = 9929.38
Sam A.
Thank you so much for your insights! I had been struggling with this problem for a few days, and greatly appreciate your guidance :)11/10/23