Bradford T. answered 11/10/23
Retired Engineer / Upper level math instructor
Volume, V= πr2h = 250
h = 250/(πr2)
Cost, C= 0.03(BottomArea + SideArea) + 0.08(TopArea)
C= 0.03(πr2+2πrh)+0.08(πr2h)
Subtituting for h
C(r) = 0.03πr2+0.06πr(250/(πr2) + 0.08πr2 = 0.11πr2 + 15/r
C'(r) = 0.22πr - 15/r2
Setting C'(r) to zero and solving for r
r3=15/(0.22π)
h = 250/(π(15/(0.22π)1/3)
C((15/(0.22π)1/3) ≈ 8 cents