The rectangle shown has a perimeter of 50 cm and the given area. Its length is 4 more than twice its width. Write and solve a system of equations to find the dimensions of the rectangle.

Answer 1

50 = 2L+2w, Perimeter= twice Length plus twice width

L=4+2w, Length = four more than twice width

25= L+w = 4+2w +w = 4+3w

3w= 25-4 = 21

w = 21/3 = 7 cm = width

L = 25-w =25-7 = 18 cm Length

2(7)+2(18)=14+36 =50