Im very confused with how to find f(x) and g(x) with the values given

Question

suppose the function f and g and their derivitives have the following values at x=1 and x=2 Let h(x)=f(g(x)) Evaluate h'(x)

x f(x) g(x) f'(x) g'(x)

1 8 2 1/3 -3

2 3 -4 2pi 5

Answer 1

h(x) = f(g(x))

By the Chain Rule, h'(x) = f'(g(x)) g'(x)

So, h'(1) = f'(g(1))g'(1) = f'(2)(-3) = (2π)(-3) = -6π

h'(2) can be found in a similar manner.