Denise G. answered 11/08/23
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
an=5(n-1)+19 formula given
For the18th term, n=18. So plug this into the formula.
a18=5(18-1)+19 = 5(17)+19 = 104
Denise G. answered 11/08/23
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
an=5(n-1)+19 formula given
For the18th term, n=18. So plug this into the formula.
a18=5(18-1)+19 = 5(17)+19 = 104
Pejman P. answered 11/08/23
B.A. in mathematics
For 18th term, n is actually 18.
Then you are looking for a18.
In the given formula substitute n=18.
You will have: a18=5(18-1)+19=5*17+19=104.
Hi Tony,
Formula for arithmetic sequence is:
an=a1 + (n-1)d
Breaking this down:
an=nth term in sequence, term we are asked to find
n=number of term we are asked to find (18 here)
d=constant difference between terms--recall that arithmetic sequences require constant difference
So, we rewrite your equation as:
an=19 + 5(n-1)
This aligns more closely with the formula and recall that addition is commutative, so this is permissible.
Now, we can assign values and substitute.
an=a18, value we are looking for
a1=19, the first term
n=18
d=5
Substituting:
a18=19 + 5(18-1)
a18=19 + 5(17)
a18=104
I hope this helps.
Mark M. answered 11/08/23
Mathematics Teacher - NCLB Highly Qualified
an = 5(n - 1) + 19
a18 = 5(18 - 1) + 19
Can you calculate and answer?
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