What is the equation of the line that passes through the point, (-7, 8) and has a slope of -1

Answer 1

Using the point-slope method, we have:

(y-y₁) = m(x-x₁)

slope: m = -1

point: (x₁,y₁) = (-7,8)

(y - (8)) = -1(x - (-7))

y -8 = -x - 7

y= -x + 1 (slope intercept form)

Answer 2

A line's general formula is (y-Y)=m×(x-X)

where m is the slope, and Y and X are any arbitrary point on the line.

for now, we have X=-7, Y=8 and m=-1

putting in the formula:

y-8= (-1) × ( x - (-7) )

now simplifying it: y-8=-x-7

simplifying more: y=-x+1