Consider the funciton f given by f(t)=log49(t7). Find values for a and b such that f(t)=a+logb(t). a= . b= 49 .

Answer 1

f(t) = log[49(t7)] = log(t7^3) = 3log7t^1/3

= 3log7 + 3logt

= about 2.5353 + 3logt^1/3

= about 2.5353+ log(t)

a= 3log7= about 2.35353,

b=t

where log = common log to base 10 = log₁₀

Unless maybe you meant log[49(t^7)]

or [log49](t7)

or [log49](t^7)

then

3 different answers