Raymond B. answered 12/06/25
Math, microeconomics or criminal justice
y = 18t - t^2
y' = 18 -2t = 0
t = 18/2 = 9 seconds to reach max height
Avril K.
asked 11/03/23Find the time it takes for a ball following the path of the parametric equations, x = 4t - 8 and y = -t^2 + 18t, to reach a maximum
Raymond B. answered 12/06/25
Math, microeconomics or criminal justice
y = 18t - t^2
y' = 18 -2t = 0
t = 18/2 = 9 seconds to reach max height
We're reaching a maximum in terms of y, so we just need to find the vertex of the y function and plug that back into the x function to see where the point is. The vertex (h, k) can be found easily with h = -b/2a = -18/2(-1) = 9. This makes the maximum at -92 + 18*9 = 81 for t=9 and thus y=81. Then plugging t=9 into the x function, we get x = 4*9 - 8 = 28.
Therefore, we have a maximum when t=9 and it occurs at the point (28, 81).
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.