For this question, remember to show all of the steps that you use to solve the problem.

Question

Given: AB · BE = CB · BD

Prove: ΔABC ~ ΔDBE

Statements | reasons

1. AB*BE = CB*BD | 1. Given

2. CB/BE = AB/BD | 2. Property of (Blank)?

3. ∠ABC ≅ ∠DBE | 3. (Blank)?

4. ΔABC ~ ΔDBE | 4. (Blank)?

Answer 1

Without having a diagram to work with it's almost impossible to help you.

BUT, I'll give it a try.

For 2. CB/BE = AB/BD, This would be the division property of equality. You are taking the equation AB · BE = CB · BD and dividing both sides by BE and then both sides by BD

For 3. ∠ABC ≅ ∠DBE, I'm going to GUESS and say they are congruent by the Vertical Angles Theorem but, again, without a diagram this is just a guess.

For 4. ΔABC ~ ΔDBE, this would be the SAS Similarity Theorem