Algebra algebra

Question

Graph the line with slope 3/4 and y-intercept 3

Answer 1

To graph a line with a slope of 3/4 and a y-intercept of 3, you can use the slope-intercept form of a linear equation, which is:

y=mx+b

where:

y is the dependent variable (vertical axis),

x is the independent variable (horizontal axis),

m is the slope, and

b is the y-intercept.

In your case, the slope (m) is 3/4, and the y-intercept (b) is 3. So, the equation for your line is:

y=3/4x+3

Now, you can plot this line on a graph:

1. Start by plotting the y-intercept, which is the point (0, 3).
2. Use the slope to find another point. Since the slope is 3/4, this means that for every 4 units to the right (positive x-direction), you go up 3 units (positive y-direction). So, from the y-intercept (0, 3), move 4 units to the right and then 3 units up to find the next point. This point is (4, 6).

Now you have two points: (0, 3) and (4, 6). You can draw a straight line that passes through these two points to graph the line.

Answer 2

Here is what your graph should look like:

https://www.desmos.com/calculator/pnzj7rgbqk

Answer 3

Use slope-intercept form

y = (3/4)x + 3