J.R. S. answered 11/18/23
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
(x ml)(0.25 M NaAc) = (100 ml)(0.15 M NaAc)
x = 60 mls NaAc buffer
(x ml)(9% NaCl) = (100 ml)(0.9% NaCl)
x = 10 mls NaCl
Procedure:
Mix 60 mls of 0.25 M sodium acetate buffer with 10 mls of 9% NaCl and dilute to a final volume of 100 mls.