I got 2 possible answers: 1. n=(A-z)/z

2. n=A/z-1

Please solve and give details for each and every step.

I got 2 possible answers: 1. n=(A-z)/z

2. n=A/z-1

Please solve and give details for each and every step.

Tutors, sign in to answer this question.

Anna,

This question is best solved by factoring. Factor the n from the right hand size of the equation, then just use algebraic rules to solve from there.

Best of luck, Steve

Philip N. | Certified 5-12 Math TeacherCertified 5-12 Math Teacher

We can use the distributive property to factor the right side of the equation for
*n*, and we get

A = nz+n **= n(z+1)**

Then, we can use the division property of equality to prepare to move *z+1* to the left side of the equation and to isolate
*n*.

A**/(z+1)** = n×(z+1)**/(z+1)**

Now, we apply the identity property of division.

A/(z+1) = n×**(z+1)/(z+1)** = n**×1 = n**

So n = A/(z+1).

We can test the solutions that you found by solving them again for A. In the first, we have the following.

n = (A-z)/z

nz = A-z

nz+z = A

Since that isn't what we started with, your solution (1) isn't correct.

For the second, we have

n = A/z-1

If that is n = (A/z)-1, then

n+1 = A/z

zn+z = A

If it is n = A/(z-1), then

n(z-1) = A

nz-n = A

That is close, but without seeing your work, it is hard to know how z+1 became z-1, which I think is where you had your error.

HTH.

Factor out n,

A = n(z+1)

Isolate n by dividing both sides by z+1,

n = A/(z+1) <==Answer

Already have an account? Log in

By signing up, I agree to Wyzant’s terms of use and privacy policy.

Or

To present the tutors that are the best fit for you, we’ll need your ZIP code.

Your Facebook email address is associated with a Wyzant tutor account. Please use a different email address to create a new student account.

Good news! It looks like you already have an account registered with the email address **you provided**.

It looks like this is your first time here. Welcome!

To present the tutors that are the best fit for you, we’ll need your ZIP code.

Please try again, our system had a problem processing your request.

Alexis G.

All-Subject/Test Prep Tutor, Specializing in Language Instruction

$11.25 per 15 min

View Profile >

Dolores A.

30 years Elem Reading, Grammar,Writing, Teacher, Author, MA Degree

$10 per 15 min

View Profile >

Bill C.

Effective Masters Grad Private Math Tutor

$10 per 15 min

View Profile >

## Comments

Apologies to Robert; my computer displayed his answer as though it had no content.