Raymond B. answered 10/26/23
Math, microeconomics or criminal justice
5 points, each pair with maximum distance apart = 1
sum 10 such distances = 10x1 = 10
if there's only 5 points, then the pairs are found using the handshake theorem
or draw a pentagon and count how many lines connect the vertices
a triangle has 3 vertices and 3 lines connecting them
a square has 4 vertices and 6 lines connecting them
the 4 sides plus 2 diagonals
a pentagon has 5 vertices and 5 diagonals = 10 pairs
BUT with 5 points some pairs on a straight linear line would have zero distance between them, while others would have the max distance of 10
the problem is a little trickier than it seems.
put one point in the middle, total sum of distances = 4 +4(1/2) = 6
at least 6, maybe more, but less than 10
if you places the 5 points equidistant, in a row, with 1/4 between each subsequent pair, the total distance is only 5