Benjamin M. answered 10/23/23
Algebra 1 Accelerator: Guiding Students to Mastery and Confidence
Hi Dieg,
I'd be happy to help!
Variables:
- E for Winston's total earnings.
- C for the number of classes he teaches.
Equations:
- Expenses: Winston spent 65 dollars on certification.
- E_expenses = 65
- Earnings: Winston earns 58 dollars per month plus 7 dollars for each class.
- E = 58 + 7C
Objective:
- Find the number of classes C Winston needs to teach to break even.
Solution:
- Set the Earnings equation equal to the Expenses equation.
- 65 = 58 + 7C
- Solve for C.
- C = 1
Interpretation and Further Exploration:
- Winston will break even—his expenses and earnings will both be 65 dollars—when he teaches just one class.
- Given that he only needs to teach one class to break even, Winston could potentially accumulate a significant profit if he teaches multiple classes per month.
- This calculation assumes that the 58-dollar base salary is guaranteed irrespective of the number of classes he teaches. If this base salary has conditions attached, the break-even point might change.
- It might also be beneficial for Winston to consider other costs, like commuting or equipment, to get a more comprehensive view of his profits and losses.
- If Winston aims for a certain profit margin or wants to recoup his initial costs within a specific timeframe, he could set targets based on these calculations.
Let me know if you have any further questions! Or, if you find this helpful, I would greatly appreciate your feedback - it is incredibly helpful since I am considered new on this platform :)
Thanks,
Ben