Solve3x-2y=10and 4x+3y=2using substitution method

Answer 1

Hi Natalie, hope this helps break down the problem for you!

Given:

3x-2y=10

4x+3y=2

Let's first isolate one of the equations to = x

You can choose either equation.

Step 1: add 2y to both sides

3x-2y=10

+2y=+2y

3x=10+2y

Step 2: Divide by 3 to both sides to isolate x

3x=10+2y

/3=/3

x=10/3+2/3y

Step 3: Plug in x=10/3+2/3y into the other equation 4x+3y= 2 to solve for y!

4(10/3+2/3y)+3y=2

Step 4: Solve for y

4(10/3+2/3y)+3y=2

40/3+8/3y+3y=2

40/3+17/3y=2

17/3y=2-40/3

y=?

Step 5: Plug y back into either of the given equations

3x-2y=10

4x+3y=2

...and solve for x!

Answer 2

3x - 2y = 10

4x + 3y = 2

From the first equation, x = (2y + 10) / 3

So, 4[(2y + 10) / 3] + 3y = 2

Solve for y, then solve for x.