Chemistry Chapter 8

Question

A gas sample has a volume of 0.203 LL with an unknown temperature. The same gas has a volume of 0.202 LL when the temperature is 37 ∘C∘C, with no change in the pressure or amount of gas.

A. What was the initial temperature, in degrees Celsius, of the gas?

Answer 1

Since pressure and number of moles are constant, we can use ...

V1/T1 = V2/ T2

V1 = initial volume = 0.203 L

T1 = initial temperature in K = ?

V2 = final volume = 0.202 L

T2 = final temperature in K = 37C + 273 = 310K

Solving for T1 we have ...

T1 = V1T2 / V2 = (0.203 L)(310K) / 0.202 L)

T1 = 311.5 K = 312 K

Converting to ºC we have ...

T1 = 312 K - 273 = 39ºC