Yi Hui L.

asked • 10/13/23

Consider the region given by

Consider the region given by

x≤1

−2 x+y ≥5

x+y−z ≤2

x,y,z ≥0


Write down the basic solution obtained by choosing x,y,z as pivots. Enter in the form (x,y,z,s1,s2,s3)

Bernard U.

To find a basic solution for the given linear programming problem by choosing x, y, and z as pivots, we first need to set up a system of equations based on the inequalities: 1. x ≤ 1 2. -2x + y ≥ 5 3. x + y - z ≤ 2 4. x, y, z ≥ 0 Let's rewrite these inequalities as equations and express the slack and surplus variables (s1, s2, s3) for the inequalities: 1. x + s1 = 1 2. -2x + y - s2 = 5 3. x + y - z + s3 = 2 4. x, y, z, s1, s2, s3 ≥ 0 Now, let's select x, y, and z as pivots and set the other variables to zero to find the basic solution: x = 1 y = 0 z = 0 Now, we can find the values of s1, s2, and s3 by plugging these values into the equations: 1. x + s1 = 1 → 1 + s1 = 1 → s1 = 0 2. -2x + y - s2 = 5 → -2(1) + 0 - s2 = 5 → -2 - s2 = 5 → s2 = -7 3. x + y - z + s3 = 2 → 1 + 0 - 0 + s3 = 2 → 1 + s3 = 2 → s3 = 1 So, the basic solution obtained by choosing x, y, and z as pivots is: (x, y, z, s1, s2, s3) = (1, 0, 0, 0, -7, 1)
Report

10/15/23

1 Expert Answer

By:

Chiranjibi G. answered • 10/15/23

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