Christian A. answered 11/17/23
Lifetime student in Bible and Higher Education.
(a) To introduce non-negative slack variables to the system of inequalities, we add the slack variables to the inequalities and make sure that their coefficients are non-negative. This gives us the following system of equations:
x1 + 2x2 − x3 + x4 = 3 x2 + 3x3 + x5 = 2 x1 ≥ 0 x2 ≥ 0 x3 ≥ 0 x4 ≥ 0 x5 ≥ 0
(b) To find the basic solution obtained by making x1 and x2 basic variables, we set x4 and x5 to 0 and solve the system of equations. This gives us:
x1 = 3 x2 = 0 x3 = 0 x4 = 0 x5 = 2
This solution is feasible because all of the variables are non-negative.
(c) To find the basic solution obtained by making x1 and x3 basic variables, we set x4 and x5 to 0 and solve the system of equations. This gives us:
x1 = 3 x2 = −1 x3 = 1 x4 = 0 x5 = 3
This solution is not feasible because x2 is negative.