Olivia M.
asked 10/09/23I would like to get a better understanding of equations
I’m in 8th grade, stuck on math homework!!
The perimeter of a rectangle is 56 cm. The length is 2cm more than the width. WHAT IS THE WIDTH?
Then I have to draw a picture of it the square, then the equation, then solve.
please help?
2 Answers By Expert Tutors

Anonymous A. answered 10/09/23
Secondary Math and Science Teacher
Hi Olivia,
Draw a rectangle and label the length (L) and width (W). Perimeter is the sum of all of the sides
P= L + W + L + W or P = 2L + 2W
Let's set W = x since it is our unknown variable. The length is 2 cm longer than the width so we can say that L = x + 2
We know the perimeter is 56 cm.
So plugging these all into our original equation, we get:
P = 2L + 2W
56 = 2(x+2) + 2x
Now we can solve this equation for x.
56 = 2x + 4 + 2x (distribute 2 to both terms in parentheses)
52 = 4x (subtract 4 from both sides and combine like terms)
13 = x (divide both sides by 4)
So the width is 13cm and the length is 15cm.
Olivia M.
Thank you so much!10/10/23
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Olivia M.
Thank you so much!10/10/23