write an equation in standard form

Question

write an equation in standard form of the line passing through the points (3,6) and (-5,10)

Answer 1

(10-6)/(-5-3) = 4//8=-1/2= slope

y -6= (-1/2)(x-3) in point slope form

or

y= -x/2 +3/2+6

y=-x/2 + 15/2 in slope intercept form

or

x+2y = 15 in standard form.

check by plugging in the points (3,6) and (-5,10)

3+2(6) = 15

-5+20 = 15