Nishant A. answered 10/07/23
MATHS IS EASY GIVE IT A FAIR CHANCE
we have h(t)=96t-16t2
it is a projectile motion.
I am using concept of derivative to find the maximum hight at the value of t
so first derivative of the given function is
96-32t
put 96-32t=0
t=3sec.
now second derivative it will be -32 which is negative so at t=3 function is maximum.
a) at t=4
height will be
96×4-16×42= 384-256
=128m
b) first derivative is the rate of change it means
(h(3.5)-h(3))÷0.5
140÷0.5
280m
c) Maximum height will be at t=3
so h(t)=96×3-16×32=288-144=144m
d) h(t)=0
96t-16t2=0
t=0,6
that implies that at t=6 ball will be at the ground
so the domain of the given function will be [0,6]
Bradford T.
Since this was posted as an algebra 1 question, probably should not answer with derivatives. Just use properties of a parabola instead or use the sketch. Also max t of the parabola can be found using t=-b/(2a) = -96/(2(-16)) = 310/07/23