introductory algebra 2

Question

What is the square root of d=t * square root of 4.9?

Answer 1

d = t√4.9

√d = √(t√4.9)

√d = (√t)(⁴√4.9)

Answer 2

sqr(d) = sqr(4.9^.5t) = about sqr(2.2136)t^.5

= about 1.488t^.5

^{possibly about +/-1.488t^.5, depending on the context of the problem}