The area of a rectangle is found by multiplying the length times the width.
The first sentence tells us that
L = 2 W + 7
So we know that the area is 22 and therefore
W (2W A+ 7) = 22
Multiplying this out and rearranging the terms gives
2 W2 + 7 W = 22
2 W2 + 7 W - 22 = 0
This is factorable by the following technique.
- multiply the coefficient of the squared term by the constant. 2 X -22 = -44
- Make a list of all the factors of 44. They are 1 and 44, 2 and 22, and 4 and 11.
- Now choose the pair so that when you make one of them negative, they add up to the middle coefficient of +7.
- The correct pair will be -4 and 11.
- Now rewrite the trinomial putting these two terms in place of the middle term.
2 W2 - 4 W + 11 W - 22.
Now factor by grouping
(2 W2 - 4 W) + (11 W - 22)
2 W (W - 2) + 11 (W - 2)
(2W + 11) ( W - 2)
Set each factor = 0 and solve.
So W = -11/2 or W = 2
Since a negative width is not acceptable, discard that answer.
So W =2. and L = 2(2) + 7 = 11
The rectangle is 11 by 2 for an area of 22.