I like to point out there is a pattern that works well when there is a variable you are solving for that is in the bottom.
Suppose
some # = some # / something we'd like to know
Let's call the first "Some#" "S".
Let's call the second one on the right "N" for numerator.
Let's call the something we'd like to know "x" with a nod to tradition.
S = N/x
If we think about the individual steps, one thing we could do is make sure the variable we are solving for isn't in the denominator by multiplying both sides by it.
S * x = (N/x) * x = N
Sx = N
Then we can isolate the variable we are solving for by dividing by S.
x = N / S
Or we could have multiplied both sides by x/S all at once.
In effect, the overall combined effect of both operations was to swap the S and the x.
This is a mental shortcut which can very effective (save time) if you are aware that it works when
a fraction equals another fraction. S can be considered S/1 (after all you can think of any number as a ratio of itself versus one if you choose to).
So if T= J/ B, then B = J/T.
Or if G=x/y, then y=x/G.
Caution though.
What if you have
B
A = -------- or in another style of typing , what if A = B/ (C+x)
C + x
Now you have to swap the entire (C+x) with A. That entire (C+x) is what you would multiply by, then divide by A, or do both at once.
Which would take you to:
C+ x = B/A
then you'd have to subtract C to finish isolating by X. Make sense?
Thank you for reading this explanation.
Please comment your conclusion about your problem, so I can congratulate you on what you've learned, or improve the explanation if it misled you.