12+2(5-3y)=-9(y-1)-2

Question

Please explain all the steps. I keep messing up this problem.

Answer 1

Original Equation: 12 + 2(5 - 3y) = -9(y - 1) - 2

Goal: Move y to the left side of the equation and the numbers to the right side.

1) Remove parentheses by foiling 2 and -9 into both sets of parentheses

12 + 10 - 6y = -9y + 9 - 2

2) Combine like terms on both sides

22 - 6y = -9y + 7

3) Subtract 22 on both sides

-6y = -9y - 15

4) Add 9y on both sides

3y = -15

5) Divide by 3 on both sides

y = -5

Answer 2

12+2(5-3y) = -9(y-1)-2

Subtract 12 from both sides

2(5-3y) = -9(y-1)-14

Distribute 2 into parentheses on the left and -9 into parentheses on the right

10-6y = -9y+9-14

Subtract 10 from both sides

-6y = -9y+9-14-10

Combine constants on right side

-6y=-9y-15

Add 9y to both sides

3y = -15

Divide both sides by 3

y = -5