The altitude and area of a trapezoid are 6 and 72, respectively. If one of the bases is 10, what is the other base?

Question

I need help with this math problem and how to solve it asap! please help

Answer 1

Area of a Trapezoid

Area = (1/2) x (sum of bases) x altitude

Rearrange

sum of bases = (2 x Area) / altitude

plugging what we know

sum of bases = (2 x 72) / 6 = 24

We also know that one of the bases is 10. So we can solve for the other base by subtracting 10 from the sum of the bases:

24-10=14

Making the other base 14.

Answer 2

Area = (b1 + b2)h/2

72= (10+14)6/2

other base is 14

average of bases times height = area

average of the bases = 12. 12x6 = 72