Please Help-Due tomorrow

Question

A boat drops its anchor. Let’s represent the anchor's elevation relative to the water's surface by the letter H (in meters) As a function of time, H=−2.4 t+75

How far does the anchor drop every 5 seconds?

Answer 1

Let’s look at the equation H = -2.4 t+75, this is the equation of a line given in its slope intercept form

y=mx+n, where m is the slope and n is the line intercept with the y axis.

In our case, n=75, y=H , and the slope m=-2.4

By definition, m=∆H÷∆t, it means that the unit drop rate is 2.4 meters/sec

Therefore, every 5 seconds we will have ∆t=5sec

Since ∆H=m∆t, we substitute and get ∆H=(2.4meters/sec)(5sec)=12 meters

Thus, for 5 seconds the anchor drops 12 meters.