Dayv O. answered 08/03/23
Caring Super Enthusiastic Knowledgeable Pre-Calculus Tutor
Can always make a plane in 3-space given three points
Using points A,B,C
find AB is vector (-3,2,2)
find AC is vector (1,2,1)
cross product provides a sized normal vector
N=2i-5j+8k
the dot product of N with (x-2,y-0,z-1)=0 provides plane ABC equation
2x-5y+8z=10
Point A was used, can use point B, or point C to find plane equation
notice that point D is on plane ABC
D=(3,-6,-3)
so A,B,C,D all on same plane
and no 3D shape possible.